One major industrial source of the greenhouse gas carbon dioxide is the heating of limestone, CaCO₃, to produce quicklime, CaO. This reaction is used in a range of industries. The equation for the decomposition of limestone is: CaCO_3(s) → CaO_(s) + CO_2(g)

a) What mass of quicklime will be produced when 10.0 tonnes of limestone is heated?

• 1 tonne = 10⁶ g
• 10.0 tonne = 10⁷ g
• n(CaCO₃) = 99900.0999mol
  ...

So I used basic stoichiometry to find out that mass is 5.60 tonnes

b) What volume of carbon dioxide gas at 500 degrees Celsius and 102 kPa will be produced in the process?

V=?, T = 500°C = 773K, P = 102kPa

V = nRT/P
= 99900.0999 x 8.31 x 773 / 102
= 6291385.085 L
= 6.29 x 10³ m³

The answer says 6.29 x 10⁴ m³

Can someone please confirm this answer?

Thanks